Comments for nafis ahmad's blog

Comment on Kiko-PHP by Nafis

Nafis — Thu, 29 Jul 2010 13:39:54 +0000

PHP speed will depend on many other things.
but in my framework it will use less processing on server and less processing in client. framework will not bring tons of extra load to do simple stuff.

Comment on 7 things I’ll Do if I am Hungry in Midnight by Donotalo

Donotalo — Thu, 29 Jul 2010 13:15:40 +0000

“Like”

Comment on Kiko-PHP by Donotalo

Donotalo — Thu, 29 Jul 2010 13:10:03 +0000

I’d like to know how do you benchmark your framework against other frameworks. How to you define your framework is “faster” or “fastest”?

Comment on how to not use mobile phones (Alternative of phone) by Donotalo

Donotalo — Thu, 29 Jul 2010 06:17:26 +0000

When I told not to use a cell phone, I meant that people shouldn’t get to you whenever they want. You will feel free. This is what I was before I buy my first cell phone. When I didn’t have a cell phone people who want to meet me or have a plan involving me would call me in land phone (or email me) at least one day before the planned occasion. It gave me time to reschedule my other tasks, if any. It gave me time to mentally prepare for those events etc.

I find it enjoyable that people cannot get to me whenever they want! For example, I don’t like to be disturbed when I’m sleeping so I turn my cell phone off before going to bed. (My cell phone is programmed to be auto shut off at 2300 daily ).

Sorry I don’t have solution to your problem. You seem to have different view than mine.

Comment on Bonus question by Nafis

Nafis — Mon, 17 May 2010 08:31:40 +0000

Answer from our teacher:
Nafis,
You got the answer right, which is 1/4*1/4*1/4*1/4.
There are two important assumption made, first one is the answerer has no clue about the right answe,r hence (s)he is unbiased toward any specific answer. Second one is, having one answer right has no bearing on the probability of having another right (or wrong), i.e. each event of giving correct answer is independent.

Lets define an event to be answering one question right.
Now, how many events were there? Obviously 4.
What is the probability of any one of the event occurring? Since there are 4 unbiased options to choose from: 1/4 .
What is the probability of having all 4 events happening? (1/4)*(1/4)*(1/4)*(1/4).

There is another way of getting to the same answer. Think about in how many ways these 4 questions could be answered: for the first question there are 4 possible ways, for the second question again 4 possible ways (this is an important point to be noted and was explicitly mentioned in the class while the exam was going on, that is, any number of question can be plotted onto one answer.), the same is true for 3rd and 4th question. Thus the total number of ways the 4 questions could be answered is 4*4*4*4. Since there is only one combination that is correct, the probability of giving all 4 correct answers (only by dint of luck) is 1/256.

Hope this puts the matter to rest. But keep the blog open, It is fun to watch people argue. It was a joy talking to a bunch of smart kids every week for 4 months. Take care.

Sabbir

Comment on About Me 2010 by Nafis

Nafis — Mon, 17 May 2010 03:28:10 +0000

I have changed the title as you have asked!
thank you for reading !

Comment on Bonus question by Nafis

Nafis — Sat, 15 May 2010 04:11:10 +0000

@miraz vai: thankx for the long talk over phone, it solved the problem.
@Nishad: You are right!
1/24 will be the right answer, the probability means: 1 / how many choice you have .. Here I have 24 options.

Comment on About Me 2010 by Donotalo

Donotalo — Fri, 14 May 2010 14:53:36 +0000

Why the title is “Me 2.0″? Souldn’t it be “Me 2010″?

Comment on Bonus question by Donotalo

Donotalo — Fri, 14 May 2010 13:39:09 +0000

Sorry didn’t notice other comments. My ISP is caching pages!

@Nafis
I think there is a mistake is your reasoning. “for the first question you have 1/4 chance for that one to be correct. then for the 2nd question its 1/3″.

For the first question, 1/4 chance that it will be correct.Say, the answer chosen for the first question matches. Given this, there is a 1/3 chance that the answer chosen for 2nd question will be correct.

Say, the answer chosen for the first question doesn’t match. And the chosen answer is actually the correct answer for question 2. Given this, there is a 0 chance that the answer chosen for 2nd question will be correct.

From the link of binomial distribution: “the binomial distribution is the discrete probability distribution of the number of successes in a sequence of n independent yes/no experiments“. The experiments have to be independent. This is the key to apply binomial distribution. But according to the question, experiments are not independent: “the probability is changing.”

Comment on Bonus question by Donotalo

Donotalo — Fri, 14 May 2010 13:24:06 +0000

Both me and one of my colleague agrees that the answer is 1/24. Explanation: Suppose, the questions are Q1, Q2, Q3 and Q4 and correct answers are A1, A2, A3 and A4 respectively. Fix the sequence Q1Q2Q3Q4. If answers are randomly chosen, the problem simplifies to arranging A1A2A3A4 in all possible ways. There are 4! = 24 possible ways. We seek the probability of matching answers for all questions and there is only 1 sequence: A1A2A3A4. So the answer is 1/24.

We also cannot believe the answer 0.968 to be true like you. If chance of getting ALL correct answers is so close to 1, students would not study for matching left & right type of questions.

Ask your instructor how s/he got so high probability and let us know.